bag contains 4 red & 5 black balls. another contains 3 red & 6 black balls. one ball is drawn from first bag & two balls from second bag. find prob that out of these three balls one is red & two are black

Asked by nishu | 17th Jun, 2013, 06:53: PM

Expert Answer:

Probability that out of the 3 balls, 2 are red and one is black would be equivalent to the sum of probability of drawing either a red ball from the first bag and then drawing a red and black ball from the second one and probability of drawing  a black ball from the first bag and then drawing 2 red balls from the second bag. 
 
So P(RRB)  = R(RB from first bag)*P(R from the second bag) + P(RR from the first bag) * P(B from the second bag)
 

Answered by  | 18th Jun, 2013, 05:13: AM

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