atom

Asked by  | 12th May, 2008, 09:02: PM

Expert Answer:

No. of moles of atoms of carbon = (0.7 10-3) /14=5  10-5 moles

Hence No. of Neutrons =8 5  10-5  Na=40 10-5 Na

where Na=Avagadaro's number

No. of emission lines= n(n-1)/2=65/2=15

Answered by  | 17th Jun, 2008, 11:15: PM

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