CBSE Class 9 Answered
atom
Asked by | 12 May, 2008, 09:02: PM
Expert Answer
No. of moles of atoms of carbon = (0.7
10-3) /14=5 10-5 moles
Hence No. of Neutrons =8 5 10-5 Na=40 10-5 Na
where Na=Avagadaro's number
No. of emission lines= n(n-1)/2=65/2=15
Answered by | 17 Jun, 2008, 11:15: PM
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