atom
Asked by | 12th May, 2008, 09:02: PM
Expert Answer:
No. of moles of atoms of carbon = (0.7 10-3) /14=5
10-5 moles
Hence No. of Neutrons =8 5
10-5
Na=40
10-5 Na
where Na=Avagadaro's number
No. of emission lines= n(n-1)/2=65/2=15
Answered by | 17th Jun, 2008, 11:15: PM
Related Videos
Kindly Sign up for a personalised experience
- Ask Study Doubts
- Sample Papers
- Past Year Papers
- Textbook Solutions
Sign Up
Verify mobile number
Enter the OTP sent to your number
Change