At what temperature will the total Kinetic energy of 0.5 mole of He be the same as the total Kinetic energy of 0.6 mol of Ne at 300 K
Asked by
| 17th Nov, 2012,
11:04: AM
Expert Answer:
K.E = n x 3/2 R T
K.E is constant ,R constant 3/2 also constant
so ,n is inversely proportional to the temperature
so we have,
n1/n2 = T2 /T1
.5 /.6 =300/T1
so, we get
T1= 300 x .6 /.5
= 360K
Answered by
| 25th Mar, 2013,
11:40: AM
Kindly Sign up for a personalised experience
- Ask Study Doubts
- Sample Papers
- Past Year Papers
- Textbook Solutions
Sign Up
Verify mobile number
Enter the OTP sent to your number
Change