At what temperature will the total Kinetic energy of 0.5 mole of He be the same as the total Kinetic energy of 0.6 mol of Ne at 300 K

Asked by  | 17th Nov, 2012, 11:04: AM

Expert Answer:

K.E = n x 3/2 R T

K.E is constant ,R constant 3/2 also constant

so ,n is inversely proportional to the temperature

so we have,

n1/n2  = T2 /T1

.5 /.6 =300/T1

so, we get

T1= 300 x .6 /.5

  = 360K

Answered by  | 25th Mar, 2013, 11:40: AM

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