at what angle a particle should b projected obliquely such that its range and maximum height be same

Asked by  | 15th Jun, 2008, 06:16: PM

Expert Answer:

Let the projectile be projected at an angle θ with speed  ‘u’ .

The horizontal range ( R ) and the maximum height ( H ) is given by,

R = u2 sin 2 θ / g            and,

H = u2 sin2 θ / 2g

As, R = H

We get,    u2 sin 2 θ / g    =    u2 sin2 θ / 2g

         Or,    2 sin θ  cos θ  =    sin2 θ / 2

         Or,    tan  θ  = 4

         Or,           θ   =  tan -1  ( 4 )

Answered by  | 17th Jun, 2008, 12:00: AM

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