CBSE Class 10 Answered
AT present Asha's age is 2 more than the square of her daughter Nisha's age.when Nisha grows to her mother's present age,Asha's age would be 1 year less than 10 times the present age of Nisha.find the present age of both Asha & Nisha.
Asked by | 04 Dec, 2010, 08:49: PM
Expert Answer
Dear student,
Lets take Asha's age = a
Nisha's age = b
a = 2 more than b2
a = 2 + b2
a = 10 times b but 1 less
a = 10b - 1
a = b2 + 2
a = 10b - 1
we have our 2 equations, now we can solve for a and b, which are Asha's and Nisha's present age, respectively.
10b - 1 = b2 + 2
b2- 10b + 3 = 0
b = 5 ± √22
im guessing you copied the quesiton wrong, since they wouldn't give you non-integer answers, like 5±√22; it's usually whole numbers.
Nisha's age = b
a = 2 more than b2
a = 2 + b2
a = 10 times b but 1 less
a = 10b - 1
a = b2 + 2
a = 10b - 1
we have our 2 equations, now we can solve for a and b, which are Asha's and Nisha's present age, respectively.
10b - 1 = b2 + 2
b2- 10b + 3 = 0
b = 5 ± √22
im guessing you copied the quesiton wrong, since they wouldn't give you non-integer answers, like 5±√22; it's usually whole numbers.
Regards,
Topper Learning Team
Answered by | 06 Dec, 2010, 10:13: AM
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