Assume , unless stated otherwise.
What length of tarpaulin 3 m wide will be required to make conical tent of height 8 m and base radius 6 m? Assume that the extra length of material that will be required for stitching margins and wastage in cutting is approximately 20 cm. (Use  = 3.14).

Solution
Height (h) of conical tent = 8 m
    Radius (r) of base of tent = 6 m
    Slant height (l) of tent =      
    CSA of conical tent =  = (3.14  6  10)  = 188.4 

Let length of tarpaulin sheet required be L. 
As 20 cm will be wasted so, effective length will be (L - 0.2 m) 
Breadth of tarpaulin = 3 m 
Area of sheet = CSA of tent 
    [(L - 0.2 m)  3] m = 188.4 
    L - 0.2 m = 62.8 m
    L = 63 m
    
    Thus, the length of the tarpaulin sheet will be 63 m.
 
elaborate last 2 points

Asked by Gajanan | 7th Dec, 2014, 01:59: PM

Expert Answer:

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Answered by Prasenjit Paul | 8th Dec, 2014, 10:26: AM