CBSE Class 10 Answered
arthematic progression
Asked by | 24 Dec, 2009, 09:11: AM
Expert Answer
The sum of such AP must be 360O
Hence,
S = n(a1+an)/2
360 = n(8 + 72)/2
n = 9
a9 = a1 + 8d
72 = 8 + 8d
d = 8
The angle in fourth sector = 8 + 3x8 = 32o
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Answered by | 24 Dec, 2009, 01:50: PM
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