Arrange the electrons represented by the following set of

 quantum number in decreasing order of energy.

 (i) n = 4, l =0, m=0 S= +

 

 

(ii) n = 2, l =1, m=1 S= -

 

 

 

 (iii) n = 3, l =2, m=0 S= +

 

 

 (iv) n = 3, l =0, m=0 S= -

 

 

 

 

Asked by Neetukhaiwal | 24th Jul, 2021, 11:18: AM

Expert Answer:

Order of energy is calculated by (n+l) rule. Orbital which is having lower (n+l) value will have lower energy and If values of (n+l) is same than orbital which is having lower value of n will have lower energy,
So, Decreasing order of energy-
(iii)>(i)>(iv)>(ii)

Answered by Ravi | 29th Jul, 2021, 11:10: AM