arithmetic progressions......

Asked by kirtichawla94 | 8th Jul, 2009, 05:40: PM

Expert Answer:

Gap between consecutive rungs =25
Total Length =250 cm
number of rungs =250/25= 10.
 length of bottom rung 45 cm
length of  top rung 25 cm
Therefore, lengths of the rungs form an AP with the first term a = 45 and
a10 = 25 cm.


Length of the wood required for the rungs = S10   =10/2[25+45]= 350 cm

It is not 385 as mentioned but 350 cm                                                              

Answered by  | 9th Jul, 2009, 09:07: AM

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