Arithmetic Progression

Asked by  | 19th Sep, 2008, 02:23: PM

Expert Answer:

(1) given a1= -1 , an=an-1/n , n  2

simply put n=2,3,4,5,6 in the expression of an

a2 = -1/2  ,a3 = -1/6 , a4 = -1/24 , a5 = -1/120  ,a6 = -1/720

(2) a1=4 , an=4an-1 + 3 , n > 1

a2=4a1 + 3= 19

a3=4a2 + 3= 79

a4=4a3 + 3= 319

a5=4a4 + 3= 1279

a6=4a5 + 3= 5119

Answered by  | 19th Sep, 2008, 09:46: PM

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