Arithmetic Progression
Asked by | 19th Sep, 2008, 02:40: PM
Expert Answer:
let no. of terms be n and c.d.= d
S = n/2(a+l) and l = a+(n-1)d => l-a = (n-1)d
d =( l2-a2) / ( k- (l+a) ) = (l-a) (l+a) / ( k- (l+a) )= (n-1)d (l+a) / ( k- (l+a) )
k- (l+a) = (n-1) (l+a)
k = n(l+a) =2S
Answered by | 19th Sep, 2008, 11:39: PM
Kindly Sign up for a personalised experience
- Ask Study Doubts
- Sample Papers
- Past Year Papers
- Textbook Solutions
Sign Up
Verify mobile number
Enter the OTP sent to your number
Change