Arithmetic Progression
Asked by
| 19th Sep, 2008,
02:40: PM
Expert Answer:
let no. of terms be n and c.d.= d
S = n/2(a+l) and l = a+(n-1)d => l-a = (n-1)d
d =( l2-a2) / ( k- (l+a) ) = (l-a) (l+a) / ( k- (l+a) )= (n-1)d (l+a) / ( k- (l+a) )
k- (l+a) = (n-1) (l+a)
k = n(l+a) =2S
Answered by
| 19th Sep, 2008,
11:39: PM
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