CBSE Class 10 Answered
arithmatic progression..
Asked by deepitapai | 08 Mar, 2009, 04:09: PM
Expert Answer
Let a be the first term.
sum of nine terms =75(given)
sum of n terms = n/2[2a+(n-1)d]
So,putting n=9 ,d=5, we get,
9/2[2a+40]=75
9[a+20]=75
3a+60=25
Solve and get the value of a
Substitute that value of a and find the nineth term
using the formula,
n th term=a+(n-1)d
Answered by | 08 Mar, 2009, 08:05: PM
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