arith metic progression
Asked by | 12th Oct, 2008, 10:22: AM
Let the four parts be a-2d , a-d , a+d , a + 2d
So a-2d + a-d + a+d + a + 2d = 20
a = 5
[(a - 2d) (a +2d) ] / [( a-d) (a + d)] = 2/3
a2 - 4 d2] / [a2 - d2 ] = 2/3
3 aa - 12 d2 = 2a2 -- 2d2
a2 - 10 d2 = 0
d = 5/ 10
So AP is (substitute in a-2d , a-d , a+d , a + 2d )
Answered by | 12th Oct, 2008, 10:31: PM
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