CBSE Class 11-science Answered
arith metic progression
Asked by | 12 Oct, 2008, 10:22: AM
Expert Answer
Let the four parts be a-2d , a-d , a+d , a + 2d
So a-2d + a-d + a+d + a + 2d = 20
a = 5
[(a - 2d) (a +2d) ] / [( a-d) (a + d)] = 2/3
a2 - 4 d2] / [a2 - d2 ] = 2/3
3 aa - 12 d2 = 2a2 -- 2d2
a2 - 10 d2 = 0
d = 5/ 10
So AP is (substitute in a-2d , a-d , a+d , a + 2d )
Answered by | 12 Oct, 2008, 10:31: PM
CBSE 11-science - Maths
Asked by benganigaurav24 | 10 Jul, 2021, 10:05: PM
ANSWERED BY EXPERT
CBSE 11-science - Maths
Asked by sahabya | 29 May, 2010, 02:55: PM
ANSWERED BY EXPERT
CBSE 11-science - Maths
Asked by abhishek11 | 25 May, 2010, 07:11: PM
ANSWERED BY EXPERT
CBSE 11-science - Maths
Asked by prashant.jain | 24 May, 2010, 12:43: PM
ANSWERED BY EXPERT
CBSE 11-science - Maths
Asked by sidhusid | 18 May, 2010, 07:14: AM
ANSWERED BY EXPERT
CBSE 11-science - Maths
Asked by MANOJKUMAR | 15 May, 2010, 01:33: PM
ANSWERED BY EXPERT
CBSE 11-science - Maths
Asked by dandirao | 15 May, 2010, 12:19: PM
ANSWERED BY EXPERT
CBSE 11-science - Maths
Asked by varunsinghal2011 | 09 May, 2010, 03:45: PM
ANSWERED BY EXPERT