CBSE Class 10 Answered
area
Asked by | 12 Mar, 2009, 11:33: AM
Expert Answer
The surface area of the remaining solid = Surface area of the cube - surface area of the hemisphere
= 6a2 - 3r2...................................(1)
According to the question,
a = 2r...............................................................................................................(2)
Substituting the value of a from (2) into equation (1) we get,
Surface Area of the remaining solid = 24r2 - 3r2
Compute the exact value.
Answered by | 13 Mar, 2009, 10:03: AM
CBSE 10 - Maths
Asked by sandeepsg9814 | 03 Mar, 2024, 10:11: PM
ANSWERED BY EXPERT
CBSE 10 - Maths
Asked by vandana | 17 Feb, 2024, 12:46: PM
ANSWERED BY EXPERT
CBSE 10 - Maths
Asked by skj809563 | 24 Nov, 2023, 09:07: PM
ANSWERED BY EXPERT
CBSE 10 - Maths
Asked by advikanagare29 | 13 Nov, 2023, 09:07: PM
ANSWERED BY EXPERT
CBSE 10 - Maths
Asked by harjinder13100 | 31 Oct, 2023, 05:48: PM
ANSWERED BY EXPERT
CBSE 10 - Maths
Asked by naveenkumarbana1 | 08 Jan, 2020, 07:38: AM
ANSWERED BY EXPERT
CBSE 10 - Maths
Asked by | 02 Jan, 2013, 09:56: AM
ANSWERED BY EXPERT
CBSE 10 - Maths
Asked by Manisha Vadagave | 18 Dec, 2012, 07:25: PM
ANSWERED BY EXPERT
CBSE 10 - Maths
Asked by Manisha Vadagave | 18 Dec, 2012, 07:23: PM
ANSWERED BY EXPERT
CBSE 10 - Maths
Asked by Manisha Vadagave | 18 Dec, 2012, 07:19: PM
ANSWERED BY EXPERT