Area of trapezium
Asked by shrivastavaabhi727 | 12th Sep, 2019, 07:53: PM
Expert Answer:
Area of trapezium = 1/2 (a + b)h
where a and b are parallel sides of trapezium and h be the height between them
Answered by Sneha shidid | 13th Sep, 2019, 09:47: AM
Related Videos
- how the two parallelograms are equal
- Area, base and corresponding altitude are x2, x-3 and x+4 respectively. Find the area of parallelogram.
- prove that parallelograms on the same base and with same area lie between the same parallels
- Please ans.
- Please solve this question
- ABCD and BCFE are parallelograms. If area of triangle EBC = 480 sq. cm. Calculate (i) area of parallelogram ABCD
(ii) area of parallelogram BCFE.
- The figure shows two parallelograms ABCD and ABEF. Prove that Area of
ADF = area of
BCE.
- ABCD is a parallelogram of area 900 sq. cm. AP is drawn perpendicular to BC and AQ is perpendicular to DC. If AP = 24 cm and AQ = 18.75 cm. Calculate (i) AB (ii) BC (iii) area of
ABC.
- The diagonals of a parallelogram ABCD intersect at point O. Through O, a line is drawn to intersect AD at P and BC at Q. Show that PQ divides the parallelogram into two parts of equal area that is ar (APQB) = ar (PQCD).
Kindly Sign up for a personalised experience
- Ask Study Doubts
- Sample Papers
- Past Year Papers
- Textbook Solutions
Sign Up
Verify mobile number
Enter the OTP sent to your number
Change