CBSE Class 10 Answered
DB = 6 cm
DE = EB = 6/2 = 3 cm
DG = radius = 6 cm.
Hence GE = 33 cm, using Pythagorus's theorem in DEG,
sin EDG = 3/2
EDG = 60
FDG = 2x60 = 120
Area of segment GBF = Area of sector DFBG - Area of triangle DFG
= πR2/3 - (1/2)(R/2)(3R)
= 22.09 sq. cm.
Area of region GEB = 22.09/2 = 11.05 sq cm.
Area of region DEBG = 2xArea of region GEB = 22.09 sq. cm.
Shaded are of one part of the total black shaded area = (1/4) area of circle with radius R - Area of region DEBG
= (1/4)(3.14)(36) - 22.09 = 6.17 sq cm.
REQUIRED SHADED AREA = 2X6.17 = 12.34 sq cm.