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# CBSE Class 10 Answered

area of shaded region?
Asked by chiku999 | 03 Feb, 2010, 07:42: PM Expert Answer DB = 6 cm

DE = EB = 6/2 = 3 cm

DG = radius = 6 cm.

Hence GE = 3 3 cm, using Pythagorus's theorem in DEG,

sin EDG = 3/2  EDG = 60  FDG = 2x60 = 120

Area of segment GBF = Area of sector DFBG - Area of triangle DFG

= πR2/3 - (1/2)(R/2)( 3R)

= 22.09 sq. cm.

Area of region GEB = 22.09/2 = 11.05 sq cm.

Area of region DEBG = 2xArea of region GEB = 22.09 sq. cm.

Shaded are of one part of the total black shaded area = (1/4) area of circle with radius R - Area of region DEBG

= (1/4)(3.14)(36) - 22.09 = 6.17 sq cm.

REQUIRED SHADED AREA = 2X6.17 = 12.34 sq cm.

Regards,

Team,

TopperLearning.

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