area of pentagon whose coordinate (4,1) (3,6) (-5,1)(-3,0)(-3,-3) using determinant of second order/
Asked by | 7th Oct, 2008, 06:08: PM
Expert Answer:
area = 1/2 [ (4.6) - ( 3.1) + (3.1) - (-5 .6) + (-5.0) - (-3.1) + (-3.-3) - (-3.0) + (-3.1) - (-3.4) ]
= 1/2 [ 24 - 3 + 3 + 30 + 0 + 3 + 9 + 0 -3 + 12 ]
= 1/2 [ 75 ]
= 75 / 2
Answered by | 29th Jan, 2009, 05:57: PM
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