area of pentagon whose coordinate (4,1) (3,6) (-5,1)(-3,0)(-3,-3) using determinant of second order/

Asked by  | 7th Oct, 2008, 06:08: PM

Expert Answer:

area = 1/2 [ (4.6) - ( 3.1) + (3.1) - (-5 .6) + (-5.0) - (-3.1) + (-3.-3) - (-3.0) + (-3.1) - (-3.4) ]

= 1/2 [ 24 - 3 + 3 + 30 + 0 + 3 + 9 + 0 -3 + 12 ]

 = 1/2 [ 75 ]

= 75 / 2

Answered by  | 29th Jan, 2009, 05:57: PM

Queries asked on Sunday & after 7pm from Monday to Saturday will be answered after 12pm the next working day.