CBSE Class 10 Answered
area of circle,sector and segment....
Asked by deepitapai | 07 Mar, 2009, 05:47: PM
Expert Answer
When each of these circles of equal radii touches the other two, the triangle formed by joining their centers is an equilaterla triangle.
So the required area
=Area of the equilateral triangle of side 2a- 3( area of one sector of central angle 60 degrees and radius a)
=
Answered by | 07 Mar, 2009, 07:53: PM
CBSE 10 - Maths
Asked by s.sreeram | 11 Mar, 2010, 08:14: PM
ANSWERED BY EXPERT
CBSE 10 - Maths
Asked by BhavSimran | 10 Mar, 2010, 12:24: PM
ANSWERED BY EXPERT
CBSE 10 - Maths
Asked by BhavSimran | 10 Mar, 2010, 12:08: PM
ANSWERED BY EXPERT
CBSE 10 - Maths
Asked by BhavSimran | 10 Mar, 2010, 12:05: PM
ANSWERED BY EXPERT