Archemedies Principle

Asked by  | 2nd Dec, 2009, 12:00: PM

Expert Answer:

The velocity of the ball just before entering the water = (2x9.8x19.6)1/2 = 19.6 m/s

Force of gravity = ρsVsg

Buoyancy force = ρwVsg

Net force = ρsVsg - ρwVsg = Vssw)g = - 500x9.8xVs

Net acceleration = Net force/mass = - 500x9.8xVs/(500xVs) = -9.8 m/s2

The time required to bring the ball to rest in water = 0 - 19.6 m/s / -9.8 m/s2 = 2 sec

The depth it goes = 2(19.6) - 9.8x2x2/2 = 19.6 m.

It'll take 2+2 = 4 seconds to come again to the water surface after entry ino water.

Regards,

Team,

TopperLearning.

Answered by  | 2nd Dec, 2009, 01:34: PM

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