A.P.
Asked by | 4th Apr, 2008, 02:07: PM
Expert Answer:
Dear student,
The number of terms in this series is = 12+22+32+42+52+62+72+82 +92+102+112+122+132+142............. = 1+4+9+16+49+64+81+100 .......= 224 + 100.... so the the desired term will be the 10th letter of the alphabetic series i.e 'j' so the answer is 'j'
Answered by | 7th Jul, 2008, 09:20: PM
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