CBSE Class 10 Answered
AP
Asked by | 06 Mar, 2008, 04:04: PM
Expert Answer
Solution:-
The desired number should be of the form
N = 3a+1 =3a'-2 = 5b+3 = 5b'-2 = 7c+5 = 7c'-2 = 9d+7 = 9d'-2 i.e. 2 less than multiple of 3,5,7,9 i.e.
LCM of 3,5,7,9 - 2 = 315 - 2 = 313 but still this number is not a four digit number so we will look for a number which is of the form 315k + 313 and close to 9999. for k = 30 we get 315*30 + 313 = 9763.
So the desired number is 9763.
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