CBSE Class 10 Answered
A.P. plzzzz hurry
Asked by khushal305 | 03 Sep, 2009, 04:44: PM
Expert Answer
The extra subscript 1 and 2 refers to the first and second AP respectively.
For example, (Sn)1 = sum of n terms for 1st AP, and so on.
(Sn)1 =n(2a1+(n-1)d1)/2
(Sn)2 =n(2a2+(n-1)d2)/2
(Sn)1/(Sn)2 = (7n+1)/(4n+27) = (2a1+(n-1)d1)/(2a2+(n-1)d2)
Taking n = 9,
64/63 = (2a1+8d1)/(2a2+8d2) = (a1+4d1)/(a2+4d2)
(a5)1 = a1+4d1
(a5)2 = a2+4d2
(a5)1/(a5)2 = (a1+4d1)/(a2+4d2) = 64/63
Regards,
Team,
TopperLearning.
Answered by | 03 Sep, 2009, 11:17: PM
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