CBSE Class 10 Answered
answer.........................................................
Asked by kirtichawla94 | 28 Oct, 2009, 07:23: PM
Expert Answer
The inradius is given by,
R = [(s-a)(s-b)(s-c)/s]1/2
Area = πR2 = π(s-a)(s-b)(s-c)/s = 154
(s-a)(s-b)(s-c)/s = 154x7/22 = 49
Let the side of equilateral triangle be a ( = b = c), then the semiperimeter, s = 3a/2.
(s-a)3/s = 49
(a/2)3/(3a/2) = 49
a2 = 49x12
a = 7x2x
3 = 24.22 cm.
Perimeter = 3a = 72.66 cm
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Team,
TopperLearning.
Answered by | 29 Oct, 2009, 12:33: AM
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