answer.........................................................

Asked by kirtichawla94 | 28th Oct, 2009, 07:23: PM

Expert Answer:

The inradius is given by,

R = [(s-a)(s-b)(s-c)/s]1/2

Area = πR2 = π(s-a)(s-b)(s-c)/s = 154

(s-a)(s-b)(s-c)/s = 154x7/22 = 49

Let the side of equilateral triangle be a ( = b = c), then the semiperimeter, s = 3a/2.

(s-a)3/s = 49

(a/2)3/(3a/2) = 49

a2 = 49x12

a = 7x2x3 = 24.22 cm.

Perimeter = 3a = 72.66 cm

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Answered by  | 29th Oct, 2009, 12:33: AM

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