Asked by  | 14th Sep, 2008, 01:24: PM

Expert Answer:

For the first drop that drops,5=(1/2)10t2

t=1 s

So the second drop dropped at t=1/2 s

s=1/2 (10)(1/4)=1.25 m

Distance of drop above the ground=5-1.25 =3.75 m


Answered by  | 14th Sep, 2008, 09:24: PM

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