Asked by  | 14th Sep, 2008, 01:23: PM

Expert Answer:

Using equation of motion ,v2 = 2gh 

Let time taken for its velocity to double is t.



And it further falls by a distance s=ut+1/2gt2 =v(v/g)+1/2g(v2 /g2 )=3v2 /2g =3h

So total distance it falls =3h+h=4h


Answered by  | 14th Sep, 2008, 09:53: PM

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