answer
Asked by
| 14th Sep, 2008,
01:23: PM
Expert Answer:
Using equation of motion ,v2 = 2gh
Let time taken for its velocity to double is t.
2v=v+gt
t=v/g
And it further falls by a distance s=ut+1/2gt2 =v(v/g)+1/2g(v2 /g2 )=3v2 /2g =3h
So total distance it falls =3h+h=4h
Answered by
| 14th Sep, 2008,
09:53: PM
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