Answer

Asked by  | 14th Sep, 2008, 11:22: PM

Expert Answer:

As per given question,

when body is dropped from height s,then using the equatuion of motion,

s=1/2g(t-1)...(1)

When height of tower is increased four times:

4s=1/2g(t-2)2   ...(2)

DIvide (1) by (2) and simplify,

t-2=2(t-1)

 

Although time comes out to be 0 in this case,so we are talking of a hypothetical situation here.

Answered by  | 15th Sep, 2008, 11:29: AM

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