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CBSE Class 10 Answered

Answer this board question plzzzz.......
Asked by Annette | 13 Mar, 2010, 02:57: PM
answered-by-expert Expert Answer

cotA=8/x  

cosecA=8x

Square the second given equation, and subtract 1 from both sides,

cosec2A = 64x2

cosec2A - 1= 64x2 - 1

cot2A = 64x2 - 1              ... using 1+cot2A = cosec2A

64/x2 = 64x2 - 1            ... but cot2A = 64/x2, from first given equation,

64(x2 - 1/x2) = 1

16x4(x2 - 1/x2) = 1

4(x2 - 1/x2)= 1/16

Regards,

Team,

TopperLearning.

Answered by | 13 Mar, 2010, 04:59: PM

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