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CBSE Class 12-science Answered

Answer please
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Asked by Varsneya Srinivas | 03 Jan, 2018, 01:43: PM
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begin mathsize 16px style Rearranging space terms open square brackets open parentheses fraction numerator straight x plus 2 over denominator straight y end fraction close parentheses squared plus fraction numerator straight x plus 2 over denominator straight y end fraction close square brackets equals dx over dy put space fraction numerator straight x plus 2 over denominator straight y end fraction equals straight t straight x plus 2 equals yt dx equals tdy plus ydt dx over dy equals straight t plus straight y dt over dy equation space becomes straight t squared plus straight t equals straight t plus straight y dt over dy straight t squared equals straight y dt over dy 1 over straight y dy equals 1 over straight t squared dt integrating logy equals negative 1 over straight t plus straight c logy equals negative fraction numerator straight y over denominator straight x plus 2 end fraction plus straight c log open parentheses straight y over straight c close parentheses equals negative fraction numerator straight y over denominator straight x plus 2 end fraction it space passes space thru space left parenthesis 1 comma 3 right parenthesis straight c equals log left parenthesis 3 right parenthesis plus 1 logy equals negative fraction numerator straight y over denominator straight x plus 2 end fraction plus log left parenthesis 3 right parenthesis plus 1 put space straight y equals straight x plus 2 you space will space get space straight y equals 3 comma space straight x equals 1 end style
Answered by Arun | 10 Jan, 2018, 06:27: PM

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CBSE 12-science - Maths
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