Answer please

Asked by Varsneya Srinivas | 3rd Jan, 2018, 01:43: PM

Expert Answer:

begin mathsize 16px style Rearranging space terms
open square brackets open parentheses fraction numerator straight x plus 2 over denominator straight y end fraction close parentheses squared plus fraction numerator straight x plus 2 over denominator straight y end fraction close square brackets equals dx over dy
put space
fraction numerator straight x plus 2 over denominator straight y end fraction equals straight t
straight x plus 2 equals yt
dx equals tdy plus ydt
dx over dy equals straight t plus straight y dt over dy
equation space becomes
straight t squared plus straight t equals straight t plus straight y dt over dy
straight t squared equals straight y dt over dy
1 over straight y dy equals 1 over straight t squared dt
integrating
logy equals negative 1 over straight t plus straight c
logy equals negative fraction numerator straight y over denominator straight x plus 2 end fraction plus straight c
log open parentheses straight y over straight c close parentheses equals negative fraction numerator straight y over denominator straight x plus 2 end fraction
it space passes space thru space left parenthesis 1 comma 3 right parenthesis
straight c equals log left parenthesis 3 right parenthesis plus 1
logy equals negative fraction numerator straight y over denominator straight x plus 2 end fraction plus log left parenthesis 3 right parenthesis plus 1
put space straight y equals straight x plus 2
you space will space get space straight y equals 3 comma space straight x equals 1


end style

Answered by Arun | 10th Jan, 2018, 06:27: PM

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