Answer is option 3 plz explain... Thanks!

Asked by jhajuhi19 | 11th Dec, 2021, 05:44: PM

Expert Answer:

begin mathsize 14px style 1 space N space equals space 1 space k g space cross times fraction numerator 1 space m over denominator s squared end fraction end style
begin mathsize 14px style 1 space N space fraction numerator m squared over denominator k g to the power of 2 to the power of space end exponent end fraction space space equals space 1 space k g space cross times fraction numerator 1 m over denominator s squared end fraction space cross times space fraction numerator m squared over denominator k g squared end fraction space equals space fraction numerator 1 space m cubed over denominator 1 space k g space cross times space s to the power of 2 to the power of space end exponent end fraction end style
 
in new unit ,  1 m = (1/10) mn   ;  1 kg = 40 kgn   ;   1 s = (1/20) sn
 
begin mathsize 14px style 1 space N space fraction numerator m cubed over denominator k g to the power of 2 to the power of space end exponent end fraction space space equals space fraction numerator 1 space m over denominator 1 space k g space cross times space s to the power of 2 to the power of space end exponent end fraction space equals space fraction numerator left parenthesis 1 divided by 1000 right parenthesis space m subscript n superscript blank over denominator 40 space k g subscript n space cross times space left parenthesis 1 divided by 400 right parenthesis space s subscript n superscript 2 space end fraction space equals space 1 over 100 space fraction numerator m subscript n superscript 3 over denominator k g subscript n space s subscript n end fraction end style
begin mathsize 14px style 6.67 space cross times space 10 to the power of negative 11 end exponent space N space fraction numerator m cubed over denominator k g to the power of 2 to the power of space end exponent end fraction space space equals space 1 over 100 space fraction numerator m subscript n superscript 3 over denominator k g subscript n space s subscript n end fraction space cross times space 6.67 space cross times space 10 to the power of negative 11 end exponent end style
hence in new system of units ,  G = 6.67 × 10-13  mn3 / ( kgn sn
 

Answered by Thiyagarajan K | 11th Dec, 2021, 08:24: PM

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