NEET Class neet Answered
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Asked by jhajuhi19 | 07 Sep, 2021, 06:59: PM
Expert Answer
When the bob is at C , we have T - mg = m ( v2 / 
) , Hence T = m g + m ( v2 / ) ..........................(1)
) , Hence T = m g + m ( v2 / ) ..........................(1)where T is tension force in the string , m is mass of bob, g is acceleration due to gravity .
The term m ( v2 / ) is centripetal force in radial direction , v is linear speed of bob and is the length of string
) is centripetal force in radial direction , v is linear speed of bob and is the length of stringWhen the bob is at A , we have T = m ( v2 / ) ................................(2)
) ................................(2)When the bob is at B , we have T = 0 (given in this case ) and mg = m ( v2 / ) .............................(3)
) .............................(3)Hence Tension is maximum when the bob is at C , reduced to zero in this case at B .
Tension force will be in between at A , i.e., greater than zero but less than the value at C .
If the bob is revolving about the point O in uniform angular speed , then its radial acceleration is same .
Since at B , we get from eqn.(3) , radial acceleration ( v2 / ) = g , then radial acceleration will be same at all point
) = g , then radial acceleration will be same at all point Hence radial acceleration at A , ( v2 / ) = g = 10 m/s2
) = g = 10 m/s2
Answered by Thiyagarajan K | 07 Sep, 2021, 08:22: PM
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