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CBSE Class 11-science Answered

Answer and explain the answer of 19th
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Asked by lovemaan5500 | 25 Jan, 2019, 03:56: PM
answered-by-expert Expert Answer
Option (b) is correct.
 
Ionisation potential = fraction numerator 2 straight pi squared 4 me to the power of 4 over denominator straight h squared end fraction 
 
The atomic number of hydrogen is 1 and helium is 2.
 
Therefore ionisation potential He2+ is four times,
 
 
equals space 13.6 cross times 4 equals space 54.4 space eV
Answered by Varsha | 27 Jan, 2019, 09:19: PM

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