Answer 5th with reaction

Asked by lovemaan5500 | 13th Jan, 2020, 09:34: PM

Expert Answer:

In case one of the alkyl group is a tertiary group in an asymmetrical ether, the halide formed is a tertiary halide.

This is because in step 2 when after the breaking of tert-carbon and -OCH3 bond, there is the formation of a more stable carbocation[(CH3)3C+], and the reaction proceeds via SN1 reaction mechanism.
Hence option 4 is the correct answer.

Answered by Ramandeep | 14th Jan, 2020, 01:07: PM