Request a call back

Join NOW to get access to exclusive study material for best results

CBSE Class 10 Answered

ans. please
Asked by shobhitdc | 25 May, 2010, 01:02: PM
answered-by-expert Expert Answer

6x2 - 7x - 3 = 0,

x = (7±(49 + 4x6x3))/12 = (7±121)/12 = (7±11)/12 = 18/12 and -3/12 i.e. 3/2  and -1/3.

Hence the roots are 3/2 and - 1/3,

Now,  arranging the quadratic equation in standard form,

x2 - 7x/6 - 3/6 = 0,

the sum of the roots should equal coefficient of x, i.e.  7/6.

3/2 - 1/3 = 7/6            .. verified,

also the product of roots be equal to constant term i.e. - 3/6,

(3/2)(-1/3) = - 3/6          ... verified.

Regards,

Team,

TopperLearning. 

Answered by | 25 May, 2010, 06:59: PM
CBSE 10 - Maths
Asked by hanugraha | 30 May, 2010, 07:53: PM
ANSWERED BY EXPERT ANSWERED BY EXPERT
CBSE 10 - Maths
Asked by hanugraha | 30 May, 2010, 07:13: PM
ANSWERED BY EXPERT ANSWERED BY EXPERT
CBSE 10 - Maths
Asked by 2806rahul | 30 May, 2010, 09:28: AM
ANSWERED BY EXPERT ANSWERED BY EXPERT
CBSE 10 - Maths
Asked by shobhitdc | 29 May, 2010, 04:59: PM
ANSWERED BY EXPERT ANSWERED BY EXPERT
CBSE 10 - Maths
Asked by ROJAAPPA | 29 May, 2010, 12:58: PM
ANSWERED BY EXPERT ANSWERED BY EXPERT
CBSE 10 - Maths
Asked by shobhitdc | 29 May, 2010, 11:59: AM
ANSWERED BY EXPERT ANSWERED BY EXPERT
CBSE 10 - Maths
Asked by shobhitdc | 29 May, 2010, 10:52: AM
ANSWERED BY EXPERT ANSWERED BY EXPERT
CBSE 10 - Maths
Asked by devanshmudgal | 28 May, 2010, 07:31: PM
ANSWERED BY EXPERT ANSWERED BY EXPERT
CBSE 10 - Maths
Asked by shobhitdc | 28 May, 2010, 01:12: PM
ANSWERED BY EXPERT ANSWERED BY EXPERT
CBSE 10 - Maths
Asked by shobhitdc | 28 May, 2010, 01:08: PM
ANSWERED BY EXPERT ANSWERED BY EXPERT
Get Latest Study Material for Academic year 24-25 Click here
×