Asked by meenatoofansingh3 | 30th Apr, 2021, 04:14: PM

Expert Answer:

According to Hardy-Weinberg equilibrium,
p2 +2pq + q2 = 1
where p2 is the frequency of homozygous genotype AA
            q2 is the frequency of genotype aa
           pq is the frequency of genotype Aa
There are 1000 individuals, out of which 360 belong to genotype AA.
p2 =360/1000 = 0.36
Then p = 0.6.

Answered by Sheetal Kolte | 3rd May, 2021, 01:17: PM

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