Angle BTC ? outside the circle

Asked by  | 30th May, 2008, 09:47: AM

Expert Answer:

the angle OCA = 23 degrees   [  [ OC is perpendiculat to the tangent CT  , so OCT =   and the adjacent  angle let us takeOCX 

    therefore  OCA = 90 - 67 = 23

   OCA = OAC  = 23 ,[  isoceles  triangle  OCA ]

    the external angle =  the sum of the internal

    67  =  23  + ATC  ===>  ATC = 67 - 23  = 44

 therefore   angle  ATC  == 44 degrees

Answered by  | 26th Jul, 2008, 03:37: PM

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