CBSE Class 10 Answered
Angle BTC ? outside the circle
Asked by | 30 May, 2008, 09:47: AM
Expert Answer
the angle OCA = 23 degrees [ [ OC is perpendiculat to the tangent CT , so OCT = and the adjacent angle let us takeOCX
therefore OCA = 90 - 67 = 23
OCA = OAC = 23 ,[ isoceles triangle OCA ]
the external angle = the sum of the internal
67 = 23 + ATC ===> ATC = 67 - 23 = 44
therefore angle ATC == 44 degrees
Answered by | 26 Jul, 2008, 03:37: PM
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