CBSE Class 11-science Answered

First, find the number of moles of each element in the sample:

40.92 x 1 mole C/ 12g C = 3.14 mole C

4.48 x 1mole H/ 1.008 g H = 4.43 mole H

54.50 x 1 mole O/ 16g O = 3.41 mole O

Dividing each of the three numbers by the smallest one (3.41 mol) gives a C:H:O moleratio of 1 :1.33 :1 and a temporary formula of Multiplying the subscripts bysmall integers in a trial-and-error procedure until whole numbers are found then givesthe empirical formula: C_{3 x 1} H_{3 x 1.33}  O_{3 x 1}  or C₃H₄O₃