an oxide of nitrogen has a vapour density 46. calculate no. of electrons in its 92g .

Asked by sunarmik das | 25th Jul, 2011, 12:30: AM

Expert Answer:

Molecular mass = 2 x vapour density
So, molecular mass = 2 x 46 = 92 u
Therefore, the molecular formula of the oxide is
The number of molecules present in 92 g of the oxide = molecules
one molecule of contains = 14 + 32 = 46 electrons
Number of electrons present in 92 g  of the oxide = 46 x6.022 x 1023 electrons
                                                                      = 2.77 x1025 electrons

Answered by  | 25th Jul, 2011, 12:14: PM

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