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CBSE Class 11-science Answered

an organic compound an analysis : c=65%, h=3.5% n = 9.6% and o= 21.9% 0.3675 gm of the
Asked by blpradhanpradhan94137 | 01 Jun, 2020, 10:46: AM
Expert Answer
Given:
 
C = 65%
H=3.5%
N=9.6%
O=21.9%
 
Mass of organic compound is 0.3675gm
 
 
 
Element     %    No. of moles  simple ratio
C 65 65/12= 5.42 5.42/0.68=7.97=8
H 3.5 3.5/1=3.5 3.5/0.68= 5.1=5
N 9.6 9.6/14=0.68 0.68/0.68=1
O 21.9 21.9/16=1.37 1.37/0.68= 2.01 =2
 
Empirical formula = C8H5NO2, mass of emperical formula = (8× 12)+(1×5)+(1×14)+(16×2) =168+5+14+32=219
Now, 53cc of compound = 0.3675gm22400 ml space of space compound space equals fraction numerator 0.3675 over denominator 53 end fraction cross times 22400 space equals 155.32

straight n space equals space fraction numerator Mol. space mass over denominator Emp. space formula space mass end fraction space equals space fraction numerator 219 over denominator 155.32 end fraction equals space 1.4 space tilde 1 space space
 
Therefore molecular formula= C8H5NO2
 
Answered by Ramandeep | 08 Jun, 2020, 01:19: PM
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