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an organic compound an analysis : c=65%, h=3.5% n = 9.6% and o= 21.9% 0.3675 gm of the
Given:

C = 65%
H=3.5%
N=9.6%
O=21.9%

Mass of organic compound is 0.3675gm

 Element % No. of moles simple ratio C 65 65/12= 5.42 5.42/0.68=7.97=8 H 3.5 3.5/1=3.5 3.5/0.68= 5.1=5 N 9.6 9.6/14=0.68 0.68/0.68=1 O 21.9 21.9/16=1.37 1.37/0.68= 2.01 =2

Empirical formula = C8H5NO2, mass of emperical formula = (8× 12)+(1×5)+(1×14)+(16×2) =168+5+14+32=219
Now, 53cc of compound = 0.3675gm

Therefore molecular formula= C8H5NO2

Answered by Ramandeep | 08 Jun, 2020, 01:19: PM

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