an object starting from rest at t= 0 with uniform acceleration cover 6m/s^2 .calculate the average speed in t= 3 to t = 5

Asked by rite2raji | 31st May, 2020, 08:24: PM

Expert Answer:

S equals u t plus 1 half a t squared
S subscript 3 equals 0 cross times 3 plus 1 half cross times 6 cross times 3 squared
S subscript 3 equals 27 m
S subscript 5 equals 0 cross times 5 plus 1 half cross times 6 cross times 5 squared
S subscript 5 equals 75 m
D i s tan c e space c o v e r e d space b e t w e e n space 3 space t o space 5 space s e c o n d s space i s

S subscript 5 minus S subscript 3
equals 75 minus 27
equals 48 m
A v e r a g e space s p e e d space equals fraction numerator T o t a l space d i s tan c e space c o v e r e d over denominator T o t a l space t i m e space t a k e n end fraction
A v e r a g e space s p e e d space equals 48 over 2 equals 24 m divided by s

Answered by Utkarsh Lokhande | 1st Jun, 2020, 07:59: AM