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CBSE Class 10 Answered

An object 30 cm high is placed perpendicular to the principal axis of a concave lens of focal length 7.5 cm. The image is formed at a distance of 5.0 cm from the lens. Calculate: (i) Distance at which object is placed, and (ii) size and nature of image formed.
Asked by Topperlearning User | 21 Jul, 2017, 03:05: PM
answered-by-expert Expert Answer

Object height, h = 3.0 cm; Focal length, f = -7.5 cm

Image distance, v = -5.0 cm (image forms on the same side as the object in concave lens)

Lens formula: 
Syntax error from line 1 column 82 to line 1 column 123. Unexpected 'mathvariant'.
 
The object is at 15 cm from the concave lens in the direction of incident ray.
Magnification,
begin mathsize 12px style straight m space equals space fraction numerator straight h apostrophe over denominator straight h end fraction space equals space straight v over straight u rightwards double arrow fraction numerator straight h apostrophe over denominator straight h end fraction space equals space fraction numerator negative space 5 over denominator negative space 15 end fraction rightwards double arrow straight h apostrophe space equals space 1 space cm end style
 
The image is virtual and erect, and its size is 1 cm.
Answered by | 21 Jul, 2017, 05:05: PM

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