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An isosceles ?ABC is inscribed in the circle x2 + y2 = 16. From points A, B and C three ordinates are drawn
which cut the ellipse x2/16+y2/9=1
at the points P, Q and R respectively such that A and P are on the
opposite sides, Q and B are on the same side and C and R are on the same side of the major axis. If ?PQR
is right angled at P and ? is the smallest angle of the ?ABC, then find the value of 16tan2? + 8 tan ? + 9.
Asked by savithakruthik9945 | 15 Jul, 2022, 21:34: PM
Expert Answer
Answered by Renu Varma | 21 Jul, 2022, 11:22: AM
JEE main - Maths
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