An inductor L of reactance XL is connected in series with a bulb B to an a.c. source .Briefly explain how does the brightness of the bulb changes when a) no. of turns of the inductor is reduced. b)a capacitor of reactance XC=XL is included in series in the same circuit

Dear student

In case of AC circuit with a bulb and L, it is similar to LR circuit.

In such a case as L will reduce in case the number of turns are reduced.

As teh instantenous current

as L lowers, the current through the circuit reduces & hence the brightness of the bulb will reduce.

In case of a capacitor being introduced such that Xc= XL,

the resonance condition is achived.

In such secenario,

Io = Vo/Z, where Z = R of the bulb i minimum.

Hence the current in te circuit will be maximum.

bulb will glow the brightest.

 

Hope that clarifies your query.

Regards

Team

Topper learning