An ideal gas expand against a constant external pressure at 2.0 atmosphere from 20 litre to 40 litre and absorb 10kJ of energy from surrounding.What is the change in internal energy of the system?(1 atm-litre = 101.3J)

Asked by  | 17th Nov, 2012, 11:15: AM

Expert Answer:

dH = dE +dnRT

10 =dE + P.dV

10 = dE + 2x 20

dE= 10-40

dE=-30KJ

Answered by  | 21st Nov, 2012, 05:32: PM

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