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CBSE Class 10 Answered

An erect image  3 times the size  of the  object is obtained with a  concave  mirror  of radius of curvature  36  cm. calculate the  position  of  the object
Asked by sisugsgsgsysyhshz | 09 Jun, 2017, 01:42: PM
answered-by-expert Expert Answer
begin mathsize 12px style For space concave space mirror colon straight m equals 3 semicolon space straight f equals straight R over 2 equals negative 18 space cm left parenthesis negative space because space it space is space straight a space concave space mirror right parenthesis From space the space formula space of space magnification colon straight m equals negative straight v over straight u therefore straight v equals negative 3 straight u From space mirror space equation colon 1 over straight v plus 1 over straight u equals 1 over straight f therefore fraction numerator 1 over denominator negative 3 straight u end fraction plus 1 over straight u equals fraction numerator 1 over denominator negative 18 end fraction fraction numerator negative 1 plus 3 over denominator 3 straight u end fraction equals fraction numerator negative 1 over denominator 18 end fraction therefore fraction numerator 2 over denominator 3 straight u end fraction equals fraction numerator negative 1 over denominator 18 end fraction therefore 3 straight u equals negative 36 therefore straight u equals negative 12 space cm end style
Answered by Romal Bhansali | 09 Jun, 2017, 03:40: PM

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