An elevator is descending with uniform acceleration. To measure the acceleration, a person in the elevator drops the coin at a moment the elevator starts. The coin is 6 ft above the floor of the elevator at the time it is dropped. the person observes that coin strikes the floor in 1 second. Calculate from these datas the accelerartion of t the elevator.

Asked by aahnik.mohanty | 27th Nov, 2017, 08:17: PM

Expert Answer:

begin mathsize 16px style l i f t space i s space m o v i n g space d o w n space w i t h space a c c e l e r a t i o n space o f space a space space space a c c e l e r a t i o n space o f c o i n space w. r. t space l i f t space equals space a c c e l e r a t i o n space o f space c o i n space w. r. t space e a r t h space minus space a c c e l e r a t i o n space o f space t h e space l i f t space space space equals space g space minus space a space equals space 9.8 space space minus space a space h e i g h t space o f space c o i n space f r o m space e l e v a t o r space f l o o r space left parenthesis s right parenthesis space equals space 6 space f t space equals 1.8288 space m t space equals space 1 space s. space space u space equals space 0 space space s space equals space u t space plus space 1 half space a t squared space equals space space space 1 half space left parenthesis 9.8 minus a right parenthesis x 1 squared space equals space space space 1 half space left parenthesis 9.8 minus a right parenthesis space space 1.8288 space equals space space space 1 half space left parenthesis 9.8 minus a right parenthesis space space a space equals space 6.2 space m divided by s squared end style

Answered by Gajendra | 28th Nov, 2017, 04:42: PM

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