An electron with speed v and a photon with speed c have the same de Broglie wavelength. If kinetic energy and momentum of electron is Ee and pe and that of photon is Eph and pph respectively, then the correct statement is

Ee/Eph=2c/v

Ee/Eph=v/2c

Pe/Pph=2c/v

Pe/Pph=v/2v

 

Asked by Vedantshinde4may | 1st Mar, 2019, 02:44: AM

Expert Answer:

Solution is attached 

Answered by Ankit K | 1st Mar, 2019, 12:41: PM

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