An electron with speed v and a photon with speed c have the same de Broglie wavelength. If kinetic energy and momentum of electron is Ee and pe and that of photon is Eph and pph respectively, then the correct statement is
Ee/Eph=2c/v
Ee/Eph=v/2c
Pe/Pph=2c/v
Pe/Pph=v/2v
Asked by Vedantshinde4may
| 1st Mar, 2019,
02:44: AM
Expert Answer:
Solution is attached 
Answered by Ankit K
| 1st Mar, 2019,
12:41: PM
Kindly Sign up for a personalised experience
- Ask Study Doubts
- Sample Papers
- Past Year Papers
- Textbook Solutions
Sign Up
Verify mobile number
Enter the OTP sent to your number
Change