Request a call back

Join NOW to get access to exclusive study material for best results

CBSE Class 12-science Answered

an electron moves in a circular orbit of radius 10 cm with a constant speed of 4000000 m/s .Determine the electric current at a point on the orbit.
Asked by Mohit | 08 Jun, 2013, 11:21: PM
answered-by-expert Expert Answer
I = dQ/dt = e*v/(2pi*r) = = 1.6022E-19 *4E6 / (2pi* 10e-2) = 1.019 E-12 A
Answered by | 09 Jun, 2013, 06:12: AM
CBSE 12-science - Physics
Asked by mailtoanjalip2005 | 16 Mar, 2024, 08:22: PM
ANSWERED BY EXPERT ANSWERED BY EXPERT
CBSE 12-science - Physics
Asked by patelnamra608 | 26 Jan, 2024, 11:01: AM
ANSWERED BY EXPERT ANSWERED BY EXPERT
CBSE 12-science - Physics
Asked by shivashikhar69 | 09 Dec, 2023, 02:27: PM
ANSWERED BY EXPERT ANSWERED BY EXPERT
CBSE 12-science - Physics
Asked by nikhilsai2616 | 19 Nov, 2023, 01:05: AM
ANSWERED BY EXPERT ANSWERED BY EXPERT
CBSE 12-science - Physics
Asked by snehashiragannavar773 | 21 Oct, 2023, 02:38: PM
ANSWERED BY EXPERT ANSWERED BY EXPERT
CBSE 12-science - Physics
Asked by dr.strange45678 | 02 Aug, 2023, 12:31: PM
ANSWERED BY EXPERT ANSWERED BY EXPERT
CBSE 12-science - Physics
Asked by komalbrar0987 | 17 May, 2023, 06:15: PM
ANSWERED BY EXPERT ANSWERED BY EXPERT
CBSE 12-science - Physics
Asked by whoami230302 | 17 Jan, 2023, 03:48: PM
ANSWERED BY EXPERT ANSWERED BY EXPERT
CBSE 12-science - Physics
Asked by amanpanday6384 | 22 Dec, 2022, 12:42: PM
ANSWERED BY EXPERT ANSWERED BY EXPERT
Get Latest Study Material for Academic year 24-25 Click here
×