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# CBSE Class 12-science Answered

An electric field E is applied between the plates a and b as shown in the figure a charge particle of mass m and charge q is projected along the direction as shown fig it's velocity v find vertical distance y covered by the partical when goes out of the electric field region
Asked by arorarajaryan2003 | 28 Apr, 2021, 10:11: PM
Force F acting on the charge q in electric field E is given as,  F = ( qE )

Acceleration a experienced by charge,  a = force / mass = (qE)/m  ..........................(1)

Vertical displacement due to electric field, y = (1/2) a t2 ..................................(2)

where t is time of travel in electric field, t  = distance / speed = x/v .........................(3)

Using eqn.(1) and eqn.(3) , we get vertical displacement y from eqn.(2) as

y = (1/2) [ (qE ) / m ] ( x / v )2

Answered by Thiyagarajan K | 29 Apr, 2021, 08:11: AM

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