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CBSE Class 12-science Answered

An electric field E is applied between the plates a and b as shown in the figure a charge particle of mass m and charge q is projected along the direction as shown fig it's velocity v find vertical distance y covered by the partical when goes out of the electric field region
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Asked by arorarajaryan2003 | 28 Apr, 2021, 10:11: PM
answered-by-expert Expert Answer
Force F acting on the charge q in electric field E is given as,  F = ( qE )
 
Acceleration a experienced by charge,  a = force / mass = (qE)/m  ..........................(1)
 
Vertical displacement due to electric field, y = (1/2) a t2 ..................................(2)
 
where t is time of travel in electric field, t  = distance / speed = x/v .........................(3)
 
Using eqn.(1) and eqn.(3) , we get vertical displacement y from eqn.(2) as
 
y = (1/2) [ (qE ) / m ] ( x / v )2
 
Answered by Thiyagarajan K | 29 Apr, 2021, 08:11: AM

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