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CBSE Class 12-science Answered

An electric dipole moment 4x10^-9 cm is aligned at 30°with the direction of a uniform electric field of magnitude 5x10^4 NC^-1.calculate the magnitude of the torque acting on the dipole? 
Asked by mayaunni486 | 06 Jul, 2020, 11:26: AM
answered-by-expert Expert Answer
D i p o l e space m o m e n t comma space p space equals space 4 cross times 10 to the power of negative 9 end exponent space C. m E l e c t r i c space f i e l d comma space E space space equals space 5 cross times 10 to the power of 4 space N divided by C space theta space equals space 30 degree T o r q u e space i s space g i v e n space b y comma space tau space equals space p space cross times E with rightwards arrow on top space equals space p E space sin theta space space equals space 4 cross times 10 to the power of negative 9 end exponent cross times 5 cross times 10 to the power of 4 cross times sin space 30 degree space equals space 10 to the power of negative 4 end exponent space N m  
Thus, magnitude of the torque acting on the dipole is 10-4 Nm 
Answered by Shiwani Sawant | 06 Jul, 2020, 02:25: PM

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