an electric bulb of power W is emitting light of a particular color of wavelength lamda. the number of photons emitted per second is-?

Asked by Abhijeet | 29th Apr, 2013, 06:23: PM

Expert Answer:

P=W
  =energy/time
 =N (hc/lambda)/time......................hc/lambda=energy associated with one photon, N=number of photons emitted per second.
 
 
W=N (hc/lambda)/time.....time=1s
N=(W x lambda)/(hc)

Answered by  | 30th Apr, 2013, 02:49: PM

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